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Python | Numpy matrix.ptp()

原文:https://www.geeksforgeeks.org/python-numpy-matrix-ptp/

借助**Numpy matrix.ptp()**方法,我们可以从给定的矩阵中得到 peek-to-peek 值,即(最大值-最小值)

语法: matrix.ptp(axis)

返回: 从给定矩阵返回对等值

示例#1 : 在这个示例中,我们可以看到,借助方法matrix.ptp(),我们能够从给定的矩阵中获得 peek-to-peek 值。

# import the important module in python
import numpy as np

# make matrix with numpy
gfg = np.matrix('[64, 1; 12, 3]')

# applying matrix.ptp() method
geeks = gfg.ptp(1)

print(geeks)

Output:

[[63]
 [ 9]]

例 2 :

# import the important module in python
import numpy as np

# make a matrix with numpy
gfg = np.matrix('[1, 2, 3; 4, 5, 6; 7, 8, -9]')

# applying matrix.ptp() method
geeks = gfg.ptp(0)

print(geeks)

Output:

[[ 6  6 15]]



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