python 中的 numpy.sqrt()
numpy.sqrt(array[, out])函数用于按元素确定数组的正平方根。
语法: numpy.sqrt()
参数: 数组:【array _ like】必须确定平方根的输入值。 out:【n 数组，可选】放置结果的备用数组对象；如果提供，其形状必须与或相同。
返回:【ndarray】返回数组中数字的平方根。
代码#1 :
# Python program explaining
# numpy.sqrt() method
# importing numpy
import numpy as geek
# applying sqrt() method on integer numbers
arr1 = geek.sqrt([1, 4, 9, 16])
arr2 = geek.sqrt([6, 10, 18])
print("square-root of an array1 : ", arr1)
print("square-root of an array2 : ", arr2)
Output:
square-root of an array1 : [ 1\. 2\. 3\. 4.]
square-root of an array2 : [ 2.44948974 3.16227766 4.24264069]
代码#2 :
# Python program explaining
# numpy.sqrt() method
# importing numpy
import numpy as geek
# applying sqrt() method on complex numbers
arr = geek.sqrt([4, -1, -5 + 9J])
print("square-root of an array : ", arr)
Output:
square-root of an array : [ 2.00000000+0.j 0.00000000+1.j 1.62721083+2.76546833j]
代码#3 :
# Python program explaining
# numpy.sqrt() method
# importing numpy
import numpy as geek
# applying sqrt() method on negative element of real numbers
arr = geek.sqrt([-4, 5, -6])
print("square-root of an array : ", arr)
Output:
RuntimeWarning: invalid value encountered in sqrt
square-root of an array : [ nan 2.23606798 nan]
