num py . isccomplexibj()在 Python
中
哎哎哎:# t0]https://www . geeksforgeeks . org/num py-isccomplexixobj-python/
numpy . is complexobj(array):这个逻辑函数有助于检查数组或复数数组的复杂类型。即使虚部等于零，它也被认为是一个复杂对象。
参数:
array : [array_like]Input array or object whose elements, we need to test.
返回:
True, if the input array has a complex element; otherwise False
代码 1 :
计算机编程语言
# Python program explaining
# iscomplexobj() function
import numpy as np
in_array = [1, 3, 5, 4]
print ("Input array : ", in_array)
output_value = np.iscomplexobj(in_array)
print ("\nIs complex : ", output_value)
输出:
Input array : [1, 3, 5, 4]
Is complex : False
代码 2 :
计算机编程语言
# Python Program illustrating
# numpy.iscomplexobj() method
import numpy as geek
# Returns True/False value for each element
a = geek.arange(20).reshape(5, 4)
print("Is complex : \n", geek.iscomplexobj(a))
# Returns True/False value as ans
# because we have mentioned dtpe in the beginning
b = geek.arange(20).reshape(5, 4).dtype = complex
print("\n",b)
print("\nIs complex : ", geek.iscomplexobj(b))
b = [[1j],
[3]]
print("\nIs complex : \n", geek.iscomplexobj(b))
输出:
Is complex :
False
class 'complex'
Is complex : False
Is complex :
True
