Python 中的 numpy.array_equiv()
哎哎哎:# t0]https://www . geeksforgeeks . org/num py-array _ equiv-pyhton/
numpy.array_equiv(arr1，arr2) : 检查两个数组是否有相同元素且形状一致的逻辑函数。
形状一致表示它们具有相同的形状，或者一个输入数组可以被广播以创建与另一个相同的形状。
参数:
arr1 : [array_like]Input array, we need to test.
arr2 : [array_like]Input array, we need to test.
返回:
True, if both arrays are equivalent; otherwise False
代码:解释工作
# Python program explaining
# array_equiv() function
import numpy as np
# input
arr1 = np.arange(4)
arr2 = [7, 4, 6, 7]
print ("arr1 : ", arr1)
print ("arr2 : ", arr2)
print ("\nResult : ", np.array_equiv(arr1, arr2))
arr1 = np.arange(4)
arr2 = np.arange(4)
print ("\n\narr1 : ", arr1)
print ("arr2 : ", arr2)
print ("\nResult : ", np.array_equiv(arr1, arr2))
arr1 = np.arange(4)
arr2 = np.arange(5)
print ("\n\narr1 : ", arr1)
print ("arr2 : ", arr2)
print ("\nResult : ", np.array_equiv(arr1, arr2))
a = np.array_equiv([1, 2], [[1, 2, 1, 2], [1, 2, 1, 2]])
b = np.array_equiv([1, 2], [[1, 2], [1, 2]])
print ("\n\na : ", a)
print ("\nb : ", b)
输出:
arr1 : [0 1 2 3]
arr2 : [7, 4, 6, 7]
Result : False
arr1 : [0 1 2 3]
arr2 : [0 1 2 3]
Result : True
arr1 : [0 1 2 3]
arr2 : [0 1 2 3 4]
Result : False
a : False
b : True
